(i) Consider a graph of shown below.
Find the slope and equation of the line joining A and B.
Let A (1,-10) be (x1,y1) and B(-2,17) be (x2,y2).
Slope is give by change in y/ change in x
Thus in this case, it will be (y1-y2)/(x1-x2)
= (-10-17)/ (1-(-2))
Equation of the line joining A and B
Take any point in the line AB to be (x, y) and (1,-10)
Then Slope remain the same thus,
Find the slope and equation of the line joining A and C.
Let A (1,-10) be (x1,y1) and C(0,1) be (x2,y2).
To find the slope= (y1-y2)/ (x1-x2)
Equation of the line AC will be
Assume a point (x, y) in the line and c(0,1)
Find the y-coordinate of the point P with x-coordinate equal to 0.5 (x=0.5.)
The equation of the curve is y=x^3-12x+1
Substitute 0.5 to x in the equation
Y= (0.5) 3-12*0.5+1
Find the slope and equation of the line joining A and P.
Let A (1,-10) be (x1, y1) and P (0.5,-4.875) be (x2,y2)
Then the slope= (y2-y1)/(x2-x1)
The equation of the line AP
Assume a point in the line (x, y) and A(1,-10)
Y=0.25-10.25X (Larson & Edwards, 2009)
(ii) Consider the function defined by
The value -2 lie in f(x)=2x-1
Set the f(x)=0 then
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