Engineering

Engineering
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Common Essay

Name Professor Course Date Smartphone Power Bank The modern developments in the levels of technology have contributed to the invention of the smartphones, which have found a wide application across the globe. People are using these phones, and once they are depleted of their charge, a power bank helps in keeping the phone in the operation mode and charges it. My question is if the power bank can be designed to store a lot of charges and even be used to charge the smartphones, why should these electrical devices be designed such that they can incorporate all the features and function efficiently as expected? On the streets, while talking via the phone and the charge dies, one just plugs the power...

Admission essay

Name Tutor's Name Course Date Admission Essay I am an engineering enthusiast. My passion for the career can be traced back to my childhood. I developed a broad sense of curiosity and interest in how things worked around me at an early age. As such, besides playing with toys, I also spent a lot of time dismantling toy cars, among other things I came across, with the intention of knowing how to repair them in case they break. During school years I was drawn even closer to engineering, and my passion and interest in the field were even further piqued by being involved and engaged in science and engineering clubs and societies. Equally important, studying and learning physics, mechanics, and mathematics...

Maintenance of Soil Water Content with Automatic Irrigation and Soil Moisture Sensor

Name: Instructor: Course: Date: Maintenance of Soil Water Content with Automatic Irrigation and Soil Moisture Sensor DISUSSION Power Supply. The power supply is connected to the microcontroller which then connected to the water pump driver and sensors. It is made of a 12/5 V battery which is used to drive the motor. The battery is charged using a photovoltaic cell which helps to convert light energy into electricity. According to (Balaji and Sudha 203), the power supply system provides electricity to be used for pumping water and transmitting signals. A charge controller within the panel helps to regulate the amount of solar power to the 12/5V battery. It maintains desirable amounts of...

Iron oxide nanoparticles coated with polyacrylic acid (PAA)

Student NameProfessor Course Date Iron Oxide Nanoparticles Coated with Polyacrylic Acid (PAA) The use of nanoparticles is showing signs of future success in the development and advancement of new biomedical applications. The property applies in areas such as cancer therapy, and drug delivery. It is also useful as a contrast agent in imagological techniques. They have chemical and physical properties such as biocompatibility and a high magnetic moment that make them useful for various new biomedical applications (Weinstein et al., 50). Several nanoparticles used for biomedical applications. However, the nanoparticles of Iron Oxide are the ones that are often used (Shubayev et al. 67). These...

revised previous paper

Student’s Name Professor’s Name Course Date Abstract The project was to help students in designing an audio mixer able, to sum up, two audio signals from different sources and combine them to one signal that can be listened to. The two audio signal sources, in this case, were the microphones and music from a mobile phone. The maximum and minimum gain allowed by the music signal was computed as 40- and 9.69-Volts peak to peak. On the other hand, the maximum and minimum gains within with a microphone could be operated to achieve the desired output was 95- and 82.75-Volts peak-to-peak. The cutoff frequency determined from the experiment for both the music and microphone were 100 kHz and 54...

Functionally and success parts

Student’s Name Professor’s Name Course Date Functionally The delivered functionality is identical to the proposed functionality. The device assists in the regular distribution of water with the assistance of soil moisture detectors that identify the water content in the soil and decide which areas require adequate watering. This system keeps optimum water levels in the plants by providing just the amount necessary. Once the ground reaches the needed moisture level, the sensors send signals, and the pump shuts off and prevents excessive water loss especially through saturation. The moisture sense remains in constant function detecting changes in the water content available in the soil, and...

Engineering

Name Lecturer Course Date AssignmentForces acting on the plank There two main effects which operate on a stationary body. They are Action and reaction forces. They can be illustrated in the figure below:- 1485900787400 4000500163195 Action Force Weight of the decorator A B 164465019748538862001974850 1028700831852787650197485 1219200197485 Reaction Force Weight of the Plank The weight of the painter and the weight of the Plank will act downward hence action force, and the rope will...

Thermodynamics Assignment Questions

Thermodynamics Assignment Questions Student’s Name Institutional Affiliation Question 1: Steam Nozzle Absolute steam pressure = 275kPa Steam quality = 0.95 Diameter of nozzle = 10mm Mass flow rate = 11kg/hr Steam pressure = 3Kpa Velocity = 700m/s Heat loss per unit volume = 50kJ/kg The steam velocity at the inlet of nozzle From first law, thermodynamics states that net energy change in any closed systems is zero (Dafermos, 2009). W=0 Hin = Enthalpy at inlet of steam = 412kj/kg +0.95(521-412) = 515.55kJ/kg Hout = Enthalpy of steam at outlet = 335+0.95(454-335) = 448.05Kj/kg 515+c22x9.81x11=448.05+11×7022x9.81+50 C = 20.37m/s Quality of steam at exit Hout=...

Stress analyses Assignmet

Stress Analyses Assignment Student’s Name Institutional Affiliation Question 1 Question 1 a The radius of curvature if an airplane is a function of the airlift and the torque The gradient is a function of the wing moment of area. The moment of area is given by product of area and square of radius of curvature (Mason, 2008). 0.209*60.16 m = X^2 * 40cmx 40cm X = 8.86 m Precision = Accuracy of the radius of curvature Upper limit = (0.2095*60.16/40cm*40cm) = 8.9M Lower limit = (0.2085*60.16 m/ (40cm*cm) = 8.84M Precision = (8.89+8.84)/2 = 1.31m (8.86- 8.85) = 0.01M Question 1 b The thickness of wing = Drawing thickness * scale of the drawing Use of similarity can calculate the...